Factoring Quadratic Equations (ac-Method & X-Factor)
Factoring Quadratics: The X-Factor Diamond, ac-Method & Difference of Squares
The X-Factor Diamond Method (Unlocking Trinomials)
Recognizing the 4 Standard Factoring Patterns
Find p and q where p · q = c and p + q = b. Example: x² + 5x + 6 = (x + 2)(x + 3).
Symmetrical square roots in conjugate pairs. Example: x² - 25 = (x - 5)(x + 5).
Multiply a · c, split the middle term, and factor by grouping pairs.
Factor out common monomials: 2x² + 6x = 2x(x + 3).
Live Factoring Step-by-Step Unravelling Timeline
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List factor pairs of 12: (1, 12), (2, 6), (3, 4). Test their sums: 1 + 12 = 13, 2 + 6 = 8, 3 + 4 = 7. The winning pair is p = 3 and q = 4!
Since leading coefficient a = 1, insert p and q directly into binomial factors: (x + 3)(x + 4) = 0.
Set each factor equal to zero and solve for x. Notice the signs flip from the factors: Roots are x = -3 and x = -4!
3 Mistakes That Destroy Scores on Factoring Exams
If the factor is (x - 5), students write the root as x = -5 ❌. When x - 5 = 0, solving gives x = +5 ✅. Signs always flip!
Factoring x² + 25 = (x + 5)(x - 5) ❌. A SUM of squares (x² + 25) is PRIME and cannot be factored over real numbers!
In 3x² - 9x = 0, factoring gives 3x(x - 3) = 0. Many students only write x = 3 and forget that 3x = 0 ➔ x = 0 is also a valid root!
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| Factoring Case | Quadratic Equation | Factored Form | Roots (Solutions) |
|---|---|---|---|
| Positive Terms (a = 1) | x² + 7x + 12 = 0 | (x + 3)(x + 4) = 0 | x = -3, -4 |
| Negative Middle (a = 1) | x² - 5x + 6 = 0 | (x - 2)(x - 3) = 0 | x = 2, 3 |
| Difference of Squares | x² - 16 = 0 | (x - 4)(x + 4) = 0 | x = ±4 |
| Hard Trinomial (a > 1) | 2x² + 7x + 3 = 0 | (2x + 1)(x + 3) = 0 | x = -1/2, -3 |
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