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Divisibility RulesFREEWorksheet Generator(Grade 4)

Divisibility Rules worksheets (Grade 4) with step-by-step answer keys. Generate unlimited unique practice sheets with fresh problems.

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Set A โ€ข 10 Qs
PanMaths.comDivisibility Rules Worksheets โ€ข Set A (Medium)
Name: __________________________
Date: _____________ Period: ____
Score: _____ / 10
1.Which of the following numbers is divisible by 3?
(A)768
(B)563
(C)164
(D)601
Workspace:
2.Which of the following numbers is divisible by 4?
(A)580
(B)734
(C)522
(D)783
Workspace:
3.Which of the following numbers is divisible by 6?
(A)204
(B)609
(C)321
(D)161
Workspace:
4.Which of the following numbers is divisible by 9?
(A)576
(B)780
(C)177
(D)427
Workspace:
5.Which of the following numbers is divisible by 3?
(A)420
(B)335
(C)284
(D)403
Workspace:
6.Which of the following numbers is divisible by 4?
(A)684
(B)713
(C)166
(D)142
Workspace:
7.Which of the following numbers is divisible by 6?
(A)324
(B)103
(C)673
(D)291
Workspace:
8.Which of the following numbers is divisible by 9?
(A)117
(B)307
(C)318
(D)327
Workspace:
9.Which of the following numbers is divisible by 3?
(A)600
(B)710
(C)631
(D)355
Workspace:
10.Which of the following numbers is divisible by 4?
(A)316
(B)613
(C)399
(D)719
Workspace:
PanMaths.com โ€ข Free Math Worksheet Generator โ€ข Set A (Medium)Page 1 of 2
PanMaths.comAnswer Key & Worked Solutions โ€ข Set A (Medium)
Answer Key
Total Problems: 10
1.Which of the following numbers is divisible by 3?
(A)768โœ“
(B)563
(C)164
(D)601
1. Divisibility Rule for 3: The sum of digits must be divisible by 3.
2. Sum of digits for 768: 7 + 6 + 8 = 21.
3. Since 21 รท 3 = 7, 768 is divisible by 3 โœ…
2.Which of the following numbers is divisible by 4?
(A)580โœ“
(B)734
(C)522
(D)783
1. Divisibility Rule for 4: A number is divisible by 4 if its last two digits form a number divisible by 4.
2. Look at the last two digits of 580: 80.
3. Since 80 รท 4 = 20, 580 is divisible by 4 โœ…
3.Which of the following numbers is divisible by 6?
(A)204โœ“
(B)609
(C)321
(D)161
1. Divisibility Rule for 6: A number must be divisible by both 2 (even) and 3 (digit sum).
2. Test for 2: Last digit 4 is even.
3. Test for 3: Digit sum 2 + 0 + 4 = 6, which is divisible by 3.
4. Therefore, 204 is divisible by 6 โœ…
4.Which of the following numbers is divisible by 9?
(A)576โœ“
(B)780
(C)177
(D)427
1. Divisibility Rule for 9: The sum of digits must be divisible by 9.
2. Sum of digits for 576: 5 + 7 + 6 = 18.
3. Since 18 รท 9 = 2, 576 is divisible by 9 โœ…
5.Which of the following numbers is divisible by 3?
(A)420โœ“
(B)335
(C)284
(D)403
1. Divisibility Rule for 3: The sum of digits must be divisible by 3.
2. Sum of digits for 420: 4 + 2 + 0 = 6.
3. Since 6 รท 3 = 2, 420 is divisible by 3 โœ…
6.Which of the following numbers is divisible by 4?
(A)684โœ“
(B)713
(C)166
(D)142
1. Divisibility Rule for 4: A number is divisible by 4 if its last two digits form a number divisible by 4.
2. Look at the last two digits of 684: 84.
3. Since 84 รท 4 = 21, 684 is divisible by 4 โœ…
7.Which of the following numbers is divisible by 6?
(A)324โœ“
(B)103
(C)673
(D)291
1. Divisibility Rule for 6: A number must be divisible by both 2 (even) and 3 (digit sum).
2. Test for 2: Last digit 4 is even.
3. Test for 3: Digit sum 3 + 2 + 4 = 9, which is divisible by 3.
4. Therefore, 324 is divisible by 6 โœ…
8.Which of the following numbers is divisible by 9?
(A)117โœ“
(B)307
(C)318
(D)327
1. Divisibility Rule for 9: The sum of digits must be divisible by 9.
2. Sum of digits for 117: 1 + 1 + 7 = 9.
3. Since 9 รท 9 = 1, 117 is divisible by 9 โœ…
9.Which of the following numbers is divisible by 3?
(A)600โœ“
(B)710
(C)631
(D)355
1. Divisibility Rule for 3: The sum of digits must be divisible by 3.
2. Sum of digits for 600: 6 + 0 + 0 = 6.
3. Since 6 รท 3 = 2, 600 is divisible by 3 โœ…
10.Which of the following numbers is divisible by 4?
(A)316โœ“
(B)613
(C)399
(D)719
1. Divisibility Rule for 4: A number is divisible by 4 if its last two digits form a number divisible by 4.
2. Look at the last two digits of 316: 16.
3. Since 16 รท 4 = 4, 316 is divisible by 4 โœ…
PanMaths.com โ€ข Answer Key & Worked SolutionsPage 2 of 2
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Worksheet Info

Categorygrade-4
Grade LevelGrade 4
DifficultyEasy, Medium, Hard, Sprint
Time5-10 min
CCSS CodeCCSS.MATH.CONTENT.4.OA.B.4

Skills Practiced

  • โœ“ Divisibility Rules

Key Strategies

  • ๐Ÿ”ข Last-Digit Rules (2, 5, 10): Check only the units digit: Divisible by 2 if last digit is even (0, 2, 4, 6, 8). Divisible by 5 if last digit is 0 or 5. Divisible by 10 if last digit is 0.
  • โž• Digit-Sum Rules (3 and 9): Add all digits together: If the sum of the digits is divisible by 3, the number is divisible by 3. If the sum of the digits is divisible by 9, the number is divisible by 9.
  • ๐Ÿ‘ฅ Combination Rule for 6: A number is divisible by 6 if and only if it passes BOTH the rule for 2 (it is even) AND the rule for 3 (the sum of its digits is a multiple of 3).
  • โœŒ๏ธ Last Two Digits Rule for 4: A number is divisible by 4 if its last two digits form a two-digit number divisible by 4 (e.g., 1,324 is divisible by 4 because 24 รท 4 = 6).
๐Ÿ“œ Standard: CCSS.MATH.CONTENT.4.OA.B.4๐Ÿ”— CCSS.MATH.CONTENT.4.OA.B.4

Mastering Divisibility Rules: Core Concepts & Mental Models

Divisibility rules provide rapid mental shortcuts to determine whether a large number can be divided by another without a remainder. Under CCSS 4.OA.B.4, fourth graders master patterns based on last digits (2, 5, 10), digit sums (3, 9), and combinations (6, 4), dramatically speeding up fraction simplification, long division, and factoring.

Worked Example & SolutionTeacher Step-by-Step Method
๐Ÿ“ Problem: Is 732 divisible by 6?
Worked Solution: 1. Test for 2: Last digit is 2 (even), so 732 is divisible by 2. 2. Test for 3: Sum of digits is 7 + 3 + 2 = 12. Since 12 is divisible by 3 (12 รท 3 = 4), 732 is divisible by 3. 3. Since 732 is divisible by both 2 and 3, it is divisible by 6 (732 รท 6 = 122). Result: Yes, 732 is divisible by 6.

๐Ÿ’ก Essential Strategies for Divisibility Rules

๐Ÿ”ข Last-Digit Rules (2, 5, 10)

Check only the units digit: Divisible by 2 if last digit is even (0, 2, 4, 6, 8). Divisible by 5 if last digit is 0 or 5. Divisible by 10 if last digit is 0.

โž• Digit-Sum Rules (3 and 9)

Add all digits together: If the sum of the digits is divisible by 3, the number is divisible by 3. If the sum of the digits is divisible by 9, the number is divisible by 9.

๐Ÿ‘ฅ Combination Rule for 6

A number is divisible by 6 if and only if it passes BOTH the rule for 2 (it is even) AND the rule for 3 (the sum of its digits is a multiple of 3).

โœŒ๏ธ Last Two Digits Rule for 4

A number is divisible by 4 if its last two digits form a two-digit number divisible by 4 (e.g., 1,324 is divisible by 4 because 24 รท 4 = 6).

โš ๏ธ Common Mistakes & Teacher Fixes

โš ๏ธApplying the last-digit rule to 3 or 9 (e.g., thinking 23 is divisible by 3 because it ends in 3)

Why students stumble: Confusing last-digit rules (which only apply to 2, 5, 10) with digit-sum rules.

Teacher Fix: For 3 and 9, you MUST add all digits together. For 23: 2 + 3 = 5 (not divisible by 3!).
Example: 23: 2 + 3 = 5 (not divisible by 3). 27: 2 + 7 = 9 (divisible by 3 and 9).
โš ๏ธChecking only 2 or only 3 when testing divisibility by 6

Why students stumble: Forgetting that 6 requires BOTH conditions to be satisfied simultaneously.

Teacher Fix: A number must be both EVEN and have a digit sum divisible by 3. 27 is divisible by 3 but odd, so NOT divisible by 6.
Example: 27 is odd โž” not divisible by 6. 36 is even and 3 + 6 = 9 โž” divisible by 6.
โš ๏ธDividing only the last digit by 4 instead of the last two digits

Why students stumble: Confusing the rule for 2 (last digit) with the rule for 4 (last two digits).

Teacher Fix: Look at the entire two-digit ending: in 514, look at 14. 14 is not divisible by 4, so 514 is not divisible by 4.
Example: 514: 14 รท 4 = 3 R 2 (not divisible by 4).

๐Ÿ“– Key Mathematical Vocabulary

Divisible

Able to be divided by another number without leaving a remainder (e.g., 18 is divisible by 3 because 18 รท 3 = 6 R 0).

Divisibility Rule

A quick mental math condition used to check if an integer divides evenly into another without performing long division.

Digit Sum

The sum obtained by adding all individual digits of a number together (e.g., for 432: 4 + 3 + 2 = 9).

Even Number

Any integer ending in 0, 2, 4, 6, or 8, indicating divisibility by 2.

โ“ Frequently Asked Questions

How do you solve a divisibility rules problem step by step?

Here is a worked example: "Is 732 divisible by 6?". Solution: 1. Test for 2: Last digit is 2 (even), so 732 is divisible by 2. 2. Test for 3: Sum of digits is 7 + 3 + 2 = 12. Since 12 is divisible by 3 (12 รท 3 = 4), 732 is divisible by 3. 3. Since 732 is divisible by both 2 and 3, it is divisible by 6 (732 รท 6 = 122). Result: Yes, 732 is divisible by 6.

What is the core learning objective for divisibility rules?

Apply divisibility tests for 2, 3, 4, 5, 6, 9, and 10 to determine whether multi-digit numbers are divisible by single-digit numbers without performing long division. This directly aligns with Common Core Standard CCSS.MATH.CONTENT.4.OA.B.4.

What is the most common mistake students make with divisibility rules?

A frequent pitfall is: "Applying the last-digit rule to 3 or 9 (e.g., thinking 23 is divisible by 3 because it ends in 3)". Why students stumble: Confusing last-digit rules (which only apply to 2, 5, 10) with digit-sum rules. How to fix it: For 3 and 9, you MUST add all digits together. For 23: 2 + 3 = 5 (not divisible by 3!). (Example: 23: 2 + 3 = 5 (not divisible by 3). 27: 2 + 7 = 9 (divisible by 3 and 9).)

How does the unlimited divisibility rules worksheet generator work?

Every click of 'Generate New Worksheet' creates a completely fresh set of divisibility rules problems with unique numbers. No two worksheets are ever the same โ€” perfect for daily practice, homework variety, and preventing student copying. You can also customize the problem count (6, 8, 10, 12, 15, or 20 problems per sheet).

Are these divisibility rules worksheets free to print with answer keys?

Yes! Every single worksheet on PanMaths is 100% free with no sign-up needed. Each sheet includes a dedicated Answer Key on Page 2 with step-by-step intermediate evaluation lines for 1-minute grading.